From 34087a9dbb0194997d109286a891f049f46ac383 Mon Sep 17 00:00:00 2001
From: Michael Chen <git@cnml.de>
Date: Tue, 17 May 2022 11:32:26 +0200
Subject: [PATCH] Added challenge 175

---
 175/crackme.py | 54 ++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 54 insertions(+)
 create mode 100644 175/crackme.py

diff --git a/175/crackme.py b/175/crackme.py
new file mode 100644
index 0000000..1875412
--- /dev/null
+++ b/175/crackme.py
@@ -0,0 +1,54 @@
+# Hiding this really important number in an obscure piece of code is brilliant!
+# AND it's encrypted!
+# We want our biggest client to know his information is safe with us.
+bezos_cc_secret = "A:4@r%uL`M-^M0c0AbcM-MFE067d3eh2bN"
+
+# Reference alphabet
+alphabet = "!\"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ"+ \
+            "[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~"
+
+
+
+def decode_secret(secret):
+    """ROT47 decode
+
+    NOTE: encode and decode are the same operation in the ROT cipher family.
+    """
+
+    # Encryption key
+    rotate_const = 47
+
+    # Storage for decoded secret
+    decoded = ""
+
+    # decode loop
+    for c in secret:
+        index = alphabet.find(c)
+        original_index = (index + rotate_const) % len(alphabet)
+        decoded = decoded + alphabet[original_index]
+
+    print(decoded)
+
+
+
+def choose_greatest():
+    """Echo the largest of the two numbers given by the user to the program
+
+    Warning: this function was written quickly and needs proper error handling
+    """
+
+    user_value_1 = input("What's your first number? ")
+    user_value_2 = input("What's your second number? ")
+    greatest_value = user_value_1 # need a value to return if 1 & 2 are equal
+
+    if user_value_1 > user_value_2:
+        greatest_value = user_value_1
+    elif user_value_1 < user_value_2:
+        greatest_value = user_value_2
+
+    print( "The number with largest positive magnitude is "
+        + str(greatest_value) )
+
+
+
+choose_greatest()